SQL Query for the Perfect Woman

SELECT ThePerfectWoman

FROM AllTheWomenInTheWorld

WHERE HerInterests Like Mine

AND CurrentMate Is Null

AND CurrentlyLives IN ( ' Yonkers' , 'Bondi>Beach ' , 'São Paulo')

GROUP BY CASE WHEN AsManyAsWillHaveMe>AsManyAsMyStaminaWillAllow

THEN AsManyAsWillHaveMe ELSE AsManyAsMyStaminaWillAllow * 2 END

HAVING Max(Libido)>=Mine